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131120312131 is a prime number
BaseRepresentation
bin111101000011101100…
…0010010111101000011
3110112102222222222221201
41322013120102331003
54122013244442011
6140122535202031
712321166156324
oct1720730227503
9415388888851
10131120312131
1150675aa8226
12214b3b16317
13c498017a13
1464bc1b444b
1536263accc1
hex1e87612f43

131120312131 has 2 divisors, whose sum is σ = 131120312132. Its totient is φ = 131120312130.

The previous prime is 131120312101. The next prime is 131120312137. The reversal of 131120312131 is 131213021131.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131120312131 is a prime.

It is a super-2 number, since 2×1311203121312 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131120312099 and 131120312108.

It is not a weakly prime, because it can be changed into another prime (131120312137) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65560156065 + 65560156066.

It is an arithmetic number, because the mean of its divisors is an integer number (65560156066).

Almost surely, 2131120312131 is an apocalyptic number.

131120312131 is a deficient number, since it is larger than the sum of its proper divisors (1).

131120312131 is an equidigital number, since it uses as much as digits as its factorization.

131120312131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 131120312131 its reverse (131213021131), we get a palindrome (262333333262).

The spelling of 131120312131 in words is "one hundred thirty-one billion, one hundred twenty million, three hundred twelve thousand, one hundred thirty-one".