Base | Representation |
---|---|
bin | 11101110100000011010011… |
… | …101001100110011010011011 |
3 | 122012020222110000122111000201 |
4 | 131310003103221212122123 |
5 | 114141233400000310412 |
6 | 1142511501235043031 |
7 | 36422062402005214 |
oct | 3564032351463233 |
9 | 565228400574021 |
10 | 131120312510107 |
11 | 388628a3126758 |
12 | 12857bb3440477 |
13 | 58217916c60bb |
14 | 245438525a40b |
15 | 1025b18445e57 |
hex | 7740d3a6669b |
131120312510107 has 2 divisors, whose sum is σ = 131120312510108. Its totient is φ = 131120312510106.
The previous prime is 131120312510059. The next prime is 131120312510189. The reversal of 131120312510107 is 701015213021131.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131120312510107 is a prime.
It is not a weakly prime, because it can be changed into another prime (131120312510197) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65560156255053 + 65560156255054.
It is an arithmetic number, because the mean of its divisors is an integer number (65560156255054).
Almost surely, 2131120312510107 is an apocalyptic number.
131120312510107 is a deficient number, since it is larger than the sum of its proper divisors (1).
131120312510107 is an equidigital number, since it uses as much as digits as its factorization.
131120312510107 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1260, while the sum is 28.
Adding to 131120312510107 its reverse (701015213021131), we get a palindrome (832135525531238).
The spelling of 131120312510107 in words is "one hundred thirty-one trillion, one hundred twenty billion, three hundred twelve million, five hundred ten thousand, one hundred seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.081 sec. • engine limits •