Base | Representation |
---|---|
bin | 111101000011101100… |
… | …0110010001011000000 |
3 | 110112110000020111100121 |
4 | 1322013120302023000 |
5 | 4122013313040000 |
6 | 140122542030024 |
7 | 12321200231164 |
oct | 1720730621300 |
9 | 415400214317 |
10 | 131120440000 |
11 | 50676085300 |
12 | 214b3b78314 |
13 | c498060c94 |
14 | 64bc208ca4 |
15 | 36263d5b1a |
hex | 1e876322c0 |
131120440000 has 210 divisors, whose sum is σ = 357394169132. Its totient is φ = 47678400000.
The previous prime is 131120439929. The next prime is 131120440021. The reversal of 131120440000 is 44021131.
It is a Harshad number since it is a multiple of its sum of digits (16).
It is an unprimeable number.
It is a polite number, since it can be written in 29 ways as a sum of consecutive naturals, for example, 4826455 + ... + 4853545.
Almost surely, 2131120440000 is an apocalyptic number.
131120440000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 131120440000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (178697084566).
131120440000 is an abundant number, since it is smaller than the sum of its proper divisors (226273729132).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131120440000 is an equidigital number, since it uses as much as digits as its factorization.
131120440000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 27145 (or 27109 counting only the distinct ones).
The product of its (nonzero) digits is 96, while the sum is 16.
Adding to 131120440000 its reverse (44021131), we get a palindrome (131164461131).
The spelling of 131120440000 in words is "one hundred thirty-one billion, one hundred twenty million, four hundred forty thousand".
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