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13112044223114 = 26556022111557
BaseRepresentation
bin1011111011001110001010…
…1111001111101010001010
31201102111110220110210120202
42332303202233033222022
53204311431310114424
643515331233052202
72522212451651114
oct276634257175212
951374426423522
1013112044223114
1141a58721519a1
1215792510b7062
137415ca8444a5
143348aa8d63b4
1517b11ae7a2ae
hexbece2bcfa8a

13112044223114 has 4 divisors (see below), whose sum is σ = 19668066334674. Its totient is φ = 6556022111556.

The previous prime is 13112044223099. The next prime is 13112044223143. The reversal of 13112044223114 is 41132244021131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 8271186185089 + 4840858038025 = 2875967^2 + 2200195^2 .

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3278011055777 + ... + 3278011055780.

Almost surely, 213112044223114 is an apocalyptic number.

13112044223114 is a deficient number, since it is larger than the sum of its proper divisors (6556022111560).

13112044223114 is an equidigital number, since it uses as much as digits as its factorization.

13112044223114 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6556022111559.

The product of its (nonzero) digits is 4608, while the sum is 29.

Adding to 13112044223114 its reverse (41132244021131), we get a palindrome (54244288244245).

The spelling of 13112044223114 in words is "thirteen trillion, one hundred twelve billion, forty-four million, two hundred twenty-three thousand, one hundred fourteen".

Divisors: 1 2 6556022111557 13112044223114