Base | Representation |
---|---|
bin | 1011111011001110001010… |
… | …1111001111101010100111 |
3 | 1201102111110220110210121211 |
4 | 2332303202233033222213 |
5 | 3204311431310120033 |
6 | 43515331233052251 |
7 | 2522212451651155 |
oct | 276634257175247 |
9 | 51374426423554 |
10 | 13112044223143 |
11 | 41a5872151a18 |
12 | 15792510b7087 |
13 | 7415ca8444c8 |
14 | 3348aa8d63d5 |
15 | 17b11ae7a2cd |
hex | bece2bcfaa7 |
13112044223143 has 2 divisors, whose sum is σ = 13112044223144. Its totient is φ = 13112044223142.
The previous prime is 13112044223099. The next prime is 13112044223171. The reversal of 13112044223143 is 34132244021131.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13112044223143 - 217 = 13112044092071 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13112044223543) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556022111571 + 6556022111572.
It is an arithmetic number, because the mean of its divisors is an integer number (6556022111572).
Almost surely, 213112044223143 is an apocalyptic number.
13112044223143 is a deficient number, since it is larger than the sum of its proper divisors (1).
13112044223143 is an equidigital number, since it uses as much as digits as its factorization.
13112044223143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 13112044223143 its reverse (34132244021131), we get a palindrome (47244288244274).
The spelling of 13112044223143 in words is "thirteen trillion, one hundred twelve billion, forty-four million, two hundred twenty-three thousand, one hundred forty-three".
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