Base | Representation |
---|---|
bin | 1111101000010… |
… | …11110110100111 |
3 | 100010201121120201 |
4 | 13310023312213 |
5 | 232031324201 |
6 | 21002211331 |
7 | 3151335442 |
oct | 764136647 |
9 | 303647521 |
10 | 131120551 |
11 | 680178a1 |
12 | 37ab3b47 |
13 | 2121b833 |
14 | 135b2659 |
15 | b7a0801 |
hex | 7d0bda7 |
131120551 has 4 divisors (see below), whose sum is σ = 131905872. Its totient is φ = 130335232.
The previous prime is 131120519. The next prime is 131120557. The reversal of 131120551 is 155021131.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 155021131 = 53 ⋅2924927.
It is a cyclic number.
It is not a de Polignac number, because 131120551 - 25 = 131120519 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131120557) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 392410 + ... + 392743.
It is an arithmetic number, because the mean of its divisors is an integer number (32976468).
Almost surely, 2131120551 is an apocalyptic number.
131120551 is a deficient number, since it is larger than the sum of its proper divisors (785321).
131120551 is an equidigital number, since it uses as much as digits as its factorization.
131120551 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 785320.
The product of its (nonzero) digits is 150, while the sum is 19.
The square root of 131120551 is about 11450.7882261441. The cubic root of 131120551 is about 508.0310485394.
Adding to 131120551 its reverse (155021131), we get a palindrome (286141682).
The spelling of 131120551 in words is "one hundred thirty-one million, one hundred twenty thousand, five hundred fifty-one".
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