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131121002999993 is a prime number
BaseRepresentation
bin11101110100000011111100…
…110011100111000010111001
3122012021001020010221000002012
4131310003330303213002321
5114141241303231444433
61142512053542415305
736422115455040236
oct3564037463470271
9565231203830065
10131121002999993
113886311796aa56
1212858166731535
1358218717858b6
14245440cc3a78d
151025b58d8a848
hex7740fcce70b9

131121002999993 has 2 divisors, whose sum is σ = 131121002999994. Its totient is φ = 131121002999992.

The previous prime is 131121002999989. The next prime is 131121003000059. The reversal of 131121002999993 is 399999200121131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 127174157231104 + 3946845768889 = 11277152^2 + 1986667^2 .

It is a cyclic number.

It is not a de Polignac number, because 131121002999993 - 22 = 131121002999989 is a prime.

It is not a weakly prime, because it can be changed into another prime (131121002929993) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65560501499996 + 65560501499997.

It is an arithmetic number, because the mean of its divisors is an integer number (65560501499997).

Almost surely, 2131121002999993 is an apocalyptic number.

It is an amenable number.

131121002999993 is a deficient number, since it is larger than the sum of its proper divisors (1).

131121002999993 is an equidigital number, since it uses as much as digits as its factorization.

131121002999993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2125764, while the sum is 59.

The spelling of 131121002999993 in words is "one hundred thirty-one trillion, one hundred twenty-one billion, two million, nine hundred ninety-nine thousand, nine hundred ninety-three".