131121003000214 has 4 divisors (see below), whose sum is σ = 196681504500324. Its totient is φ = 65560501500106.

The previous prime is 131121003000193. The next prime is 131121003000227. The reversal of 131121003000214 is 412000300121131.

It is a semiprime because it is the product of two primes.

It is a junction number, because it is equal to n+sod(n) for n = 131121003000191 and 131121003000200.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32780250750052 + ... + 32780250750055.

It is an arithmetic number, because the mean of its divisors is an integer number (49170376125081).

Almost surely, 2^{131121003000214} is an apocalyptic number.

131121003000214 is a deficient number, since it is larger than the sum of its proper divisors (65560501500110).

131121003000214 is an equidigital number, since it uses as much as digits as its factorization.

131121003000214 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 65560501500109.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 131121003000214 its reverse (412000300121131), we get a palindrome (543121303121345).

The spelling of 131121003000214 in words is "one hundred thirty-one trillion, one hundred twenty-one billion, three million, two hundred fourteen", and thus it is an aban number.