13112112102320 has 640 divisors, whose sum is σ = 41243485962240. Its totient is φ = 3753830338560.

The previous prime is 13112112102311. The next prime is 13112112102347. The reversal of 13112112102320 is 2320121121131.

It is a super-3 number, since 3×13112112102320³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a junction number, because it is equal to n+sod(n) for n = 13112112102292 and 13112112102301.

It is an unprimeable number.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 588583022 + ... + 588605298.

It is an arithmetic number, because the mean of its divisors is an integer number (64442946816).

Almost surely, 2^{13112112102320} is an apocalyptic number.

13112112102320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13112112102320, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (20621742981120).

13112112102320 is an abundant number, since it is smaller than the sum of its proper divisors (28131373859920).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13112112102320 is a wasteful number, since it uses less digits than its factorization.

13112112102320 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 22481 (or 22475 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 13112112102320 its reverse (2320121121131), we get a palindrome (15432233223451).

The spelling of 13112112102320 in words is "thirteen trillion, one hundred twelve billion, one hundred twelve million, one hundred two thousand, three hundred twenty".