13112113103 has 4 divisors (see below), whose sum is σ = 13112365320. Its totient is φ = 13111860888.

The previous prime is 13112113097. The next prime is 13112113181. The reversal of 13112113103 is 30131121131.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30131121131 = 199 ⋅151412669.

It is a cyclic number.

It is not a de Polignac number, because 13112113103 - 2¹² = 13112109007 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13112113193) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16193 + ... + 162746.

It is an arithmetic number, because the mean of its divisors is an integer number (3278091330).

Almost surely, 2^13112113103 is an apocalyptic number.

13112113103 is a deficient number, since it is larger than the sum of its proper divisors (252217).

13112113103 is an equidigital number, since it uses as much as digits as its factorization.

13112113103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 252216.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 13112113103 its reverse (30131121131), we get a palindrome (43243234234).

The spelling of 13112113103 in words is "thirteen billion, one hundred twelve million, one hundred thirteen thousand, one hundred three".