Base | Representation |
---|---|
bin | 1011111011001110011011… |
… | …0110000010010010010010 |
3 | 1201102111122201002201122202 |
4 | 2332303212312002102102 |
5 | 3204312101424042320 |
6 | 43515342133403202 |
7 | 2522214246340010 |
oct | 276634666022222 |
9 | 51374581081582 |
10 | 13112113112210 |
11 | 41a58a8024332 |
12 | 1579270199502 |
13 | 74160bbb4478 |
14 | 3348b5b098b0 |
15 | 17b122036b75 |
hex | bece6d82492 |
13112113112210 has 16 divisors (see below), whose sum is σ = 26973489830976. Its totient is φ = 4495581638448.
The previous prime is 13112113112191. The next prime is 13112113112213. The reversal of 13112113112210 is 1221131121131.
13112113112210 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not an unprimeable number, because it can be changed into a prime (13112113112213) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 93657950732 + ... + 93657950871.
It is an arithmetic number, because the mean of its divisors is an integer number (1685843114436).
Almost surely, 213112113112210 is an apocalyptic number.
13112113112210 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13112113112210 is an abundant number, since it is smaller than the sum of its proper divisors (13861376718766).
13112113112210 is a wasteful number, since it uses less digits than its factorization.
13112113112210 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 187315901617.
The product of its (nonzero) digits is 72, while the sum is 20.
Adding to 13112113112210 its reverse (1221131121131), we get a palindrome (14333244233341).
The spelling of 13112113112210 in words is "thirteen trillion, one hundred twelve billion, one hundred thirteen million, one hundred twelve thousand, two hundred ten".
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