Base | Representation |
---|---|
bin | 10011000101001010010… |
… | …110011101001101111011 |
3 | 11122100110122111201022011 |
4 | 103011022112131031323 |
5 | 132440330340113412 |
6 | 2442210200510351 |
7 | 163506031504333 |
oct | 23051226351573 |
9 | 4570418451264 |
10 | 1311212426107 |
11 | 46609a25a951 |
12 | 19215647b3b7 |
13 | 96854039cbc |
14 | 4766a7540c3 |
15 | 241934757a7 |
hex | 1314a59d37b |
1311212426107 has 2 divisors, whose sum is σ = 1311212426108. Its totient is φ = 1311212426106.
The previous prime is 1311212426093. The next prime is 1311212426171. The reversal of 1311212426107 is 7016242121131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1311212426107 - 223 = 1311204037499 is a prime.
It is not a weakly prime, because it can be changed into another prime (1311212426207) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655606213053 + 655606213054.
It is an arithmetic number, because the mean of its divisors is an integer number (655606213054).
Almost surely, 21311212426107 is an apocalyptic number.
1311212426107 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311212426107 is an equidigital number, since it uses as much as digits as its factorization.
1311212426107 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4032, while the sum is 31.
Adding to 1311212426107 its reverse (7016242121131), we get a palindrome (8327454547238).
The spelling of 1311212426107 in words is "one trillion, three hundred eleven billion, two hundred twelve million, four hundred twenty-six thousand, one hundred seven".
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