Base | Representation |
---|---|
bin | 11101110100000100001110… |
… | …110001110010101110101111 |
3 | 122012021002000011021110210110 |
4 | 131310010032301302232233 |
5 | 114141242412423412310 |
6 | 1142512143513111103 |
7 | 36422126105622234 |
oct | 3564041661625657 |
9 | 565232004243713 |
10 | 131121304513455 |
11 | 38863262088533 |
12 | 1285822b6b8493 |
13 | 58218bc093529 |
14 | 245443acc578b |
15 | 1025b75597d20 |
hex | 77410ec72baf |
131121304513455 has 16 divisors (see below), whose sum is σ = 209808342795744. Its totient is φ = 69926610549120.
The previous prime is 131121304513351. The next prime is 131121304513471. The reversal of 131121304513455 is 554315403121131.
It is not a de Polignac number, because 131121304513455 - 212 = 131121304509359 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 296763016 + ... + 297204525.
It is an arithmetic number, because the mean of its divisors is an integer number (13113021424734).
Almost surely, 2131121304513455 is an apocalyptic number.
131121304513455 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
131121304513455 is a deficient number, since it is larger than the sum of its proper divisors (78687038282289).
131121304513455 is a wasteful number, since it uses less digits than its factorization.
131121304513455 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 593982266.
The product of its (nonzero) digits is 108000, while the sum is 39.
Adding to 131121304513455 its reverse (554315403121131), we get a palindrome (685436707634586).
The spelling of 131121304513455 in words is "one hundred thirty-one trillion, one hundred twenty-one billion, three hundred four million, five hundred thirteen thousand, four hundred fifty-five".
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