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131121304509359 is a prime number
BaseRepresentation
bin11101110100000100001110…
…110001110001101110101111
3122012021002000011021021011202
4131310010032301301232233
5114141242412423244414
61142512143513040115
736422126105604263
oct3564041661615657
9565232004237152
10131121304509359
113886326208544a
121285822b6b603b
1358218bc0916c8
14245443acc40a3
151025b755969de
hex77410ec71baf

131121304509359 has 2 divisors, whose sum is σ = 131121304509360. Its totient is φ = 131121304509358.

The previous prime is 131121304509313. The next prime is 131121304509401. The reversal of 131121304509359 is 953905403121131.

It is a happy number.

It is a strong prime.

It is an emirp because it is prime and its reverse (953905403121131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131121304509359 - 220 = 131121303460783 is a prime.

It is a super-3 number, since 3×1311213045093593 (a number of 43 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131121304509059) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65560652254679 + 65560652254680.

It is an arithmetic number, because the mean of its divisors is an integer number (65560652254680).

Almost surely, 2131121304509359 is an apocalyptic number.

131121304509359 is a deficient number, since it is larger than the sum of its proper divisors (1).

131121304509359 is an equidigital number, since it uses as much as digits as its factorization.

131121304509359 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 437400, while the sum is 47.

The spelling of 131121304509359 in words is "one hundred thirty-one trillion, one hundred twenty-one billion, three hundred four million, five hundred nine thousand, three hundred fifty-nine".