Base | Representation |
---|---|
bin | 10011000101001010011… |
… | …001000010100001001001 |
3 | 11122100110200210010001211 |
4 | 103011022121002201021 |
5 | 132440331023300202 |
6 | 2442210223213121 |
7 | 163506040324315 |
oct | 23051231024111 |
9 | 4570420703054 |
10 | 1311213103177 |
11 | 46609a68260a |
12 | 1921567471a1 |
13 | 96854216233 |
14 | 4766a88cb45 |
15 | 2419355b1d7 |
hex | 1314a642849 |
1311213103177 has 2 divisors, whose sum is σ = 1311213103178. Its totient is φ = 1311213103176.
The previous prime is 1311213103127. The next prime is 1311213103201. The reversal of 1311213103177 is 7713013121131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1280283198016 + 30929905161 = 1131496^2 + 175869^2 .
It is an emirp because it is prime and its reverse (7713013121131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1311213103177 - 231 = 1309065619529 is a prime.
It is not a weakly prime, because it can be changed into another prime (1311213103117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655606551588 + 655606551589.
It is an arithmetic number, because the mean of its divisors is an integer number (655606551589).
Almost surely, 21311213103177 is an apocalyptic number.
It is an amenable number.
1311213103177 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311213103177 is an equidigital number, since it uses as much as digits as its factorization.
1311213103177 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2646, while the sum is 31.
The spelling of 1311213103177 in words is "one trillion, three hundred eleven billion, two hundred thirteen million, one hundred three thousand, one hundred seventy-seven".
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