Base | Representation |
---|---|
bin | 1011111011001110100000… |
… | …0011011011101010001000 |
3 | 1201102111201010021111221201 |
4 | 2332303220003123222020 |
5 | 3204312122122314344 |
6 | 43515344140313544 |
7 | 2522214613651444 |
oct | 276635003335210 |
9 | 51374633244851 |
10 | 13112133401224 |
11 | 41a5908521810 |
12 | 1579276b428b4 |
13 | 7416131692c0 |
14 | 3348b86ab824 |
15 | 17b123be34d4 |
hex | bece80dba88 |
13112133401224 has 32 divisors (see below), whose sum is σ = 28883370781440. Its totient is φ = 5501594433600.
The previous prime is 13112133401189. The next prime is 13112133401251. The reversal of 13112133401224 is 42210433121131.
13112133401224 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 13112133401192 and 13112133401201.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5730826392 + ... + 5730828679.
It is an arithmetic number, because the mean of its divisors is an integer number (902605336920).
Almost surely, 213112133401224 is an apocalyptic number.
It is an amenable number.
13112133401224 is an abundant number, since it is smaller than the sum of its proper divisors (15771237380216).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13112133401224 is a wasteful number, since it uses less digits than its factorization.
13112133401224 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11461655101 (or 11461655097 counting only the distinct ones).
The product of its (nonzero) digits is 3456, while the sum is 28.
Adding to 13112133401224 its reverse (42210433121131), we get a palindrome (55322566522355).
The spelling of 13112133401224 in words is "thirteen trillion, one hundred twelve billion, one hundred thirty-three million, four hundred one thousand, two hundred twenty-four".
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