Base | Representation |
---|---|
bin | 10011000101001010100… |
… | …100100011010100101011 |
3 | 11122100110220110102220220 |
4 | 103011022210203110223 |
5 | 132440332311334011 |
6 | 2442210412021123 |
7 | 163506105064110 |
oct | 23051244432453 |
9 | 4570426412826 |
10 | 1311216121131 |
11 | 4660a1353a94 |
12 | 1921577617a3 |
13 | 96854a31ac7 |
14 | 4766b036907 |
15 | 24193955506 |
hex | 1314a92352b |
1311216121131 has 8 divisors (see below), whose sum is σ = 1998043613184. Its totient is φ = 749266354920.
The previous prime is 1311216121081. The next prime is 1311216121157.
It is a happy number.
1311216121131 is nontrivially palindromic in base 10.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 1311216121131 - 217 = 1311215990059 is a prime.
It is a super-2 number, since 2×13112161211312 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1311216121331) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 31219431435 + ... + 31219431476.
It is an arithmetic number, because the mean of its divisors is an integer number (249755451648).
Almost surely, 21311216121131 is an apocalyptic number.
1311216121131 is a deficient number, since it is larger than the sum of its proper divisors (686827492053).
1311216121131 is an equidigital number, since it uses as much as digits as its factorization.
1311216121131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 62438862921.
The product of its digits is 216, while the sum is 24.
The spelling of 1311216121131 in words is "one trillion, three hundred eleven billion, two hundred sixteen million, one hundred twenty-one thousand, one hundred thirty-one".
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