Search a number
-
+
13112221131000 = 2332536752141737
BaseRepresentation
bin1011111011001110110101…
…0010000110000011111000
31201102111221020100122120200
42332303231102012003320
53204312312102143000
643515400552522200
72522220030440415
oct276635522060370
951374836318520
1013112221131000
1141a5952aa2462
1215792a03b0360
137416283a4b04
143348c61c710c
1517b12b772500
hexbeced4860f8

13112221131000 has 384 divisors, whose sum is σ = 45068204900160. Its totient is φ = 3437710848000.

The previous prime is 13112221130959. The next prime is 13112221131071. The reversal of 13112221131000 is 13112221131.

13112221131000 is a `hidden beast` number, since 1 + 311 + 2 + 221 + 131 + 0 + 0 + 0 = 666.

It is a super-2 number, since 2×131122211310002 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 314142132 + ... + 314183868.

Almost surely, 213112221131000 is an apocalyptic number.

13112221131000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13112221131000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (22534102450080).

13112221131000 is an abundant number, since it is smaller than the sum of its proper divisors (31955983769160).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13112221131000 is a wasteful number, since it uses less digits than its factorization.

13112221131000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 42352 (or 42335 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 18.

Adding to 13112221131000 its reverse (13112221131), we get a palindrome (13125333352131).

13112221131000 divided by its reverse (13112221131) gives a cube (1000 = 103).

The spelling of 13112221131000 in words is "thirteen trillion, one hundred twelve billion, two hundred twenty-one million, one hundred thirty-one thousand".