13112222113231 has 4 divisors (see below), whose sum is σ = 13112386102152. Its totient is φ = 13112058124312.

The previous prime is 13112222113229. The next prime is 13112222113241. The reversal of 13112222113231 is 13231122221131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13112222113231 - 2¹ = 13112222113229 is a prime.

It is a super-3 number, since 3×13112222113231³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13112222113196 and 13112222113205.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13112222113201) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 81874465 + ... + 82034458.

It is an arithmetic number, because the mean of its divisors is an integer number (3278096525538).

Almost surely, 2^{13112222113231} is an apocalyptic number.

13112222113231 is a deficient number, since it is larger than the sum of its proper divisors (163988921).

13112222113231 is an equidigital number, since it uses as much as digits as its factorization.

13112222113231 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 163988920.

The product of its digits is 864, while the sum is 25.

Adding to 13112222113231 its reverse (13231122221131), we get a palindrome (26343344334362).

The spelling of 13112222113231 in words is "thirteen trillion, one hundred twelve billion, two hundred twenty-two million, one hundred thirteen thousand, two hundred thirty-one".