Base | Representation |
---|---|
bin | 1011111011001110110101… |
… | …0101110101110111111001 |
3 | 1201102111221022012120000011 |
4 | 2332303231111311313321 |
5 | 3204312312330111043 |
6 | 43515401025541521 |
7 | 2522220042001243 |
oct | 276635525656771 |
9 | 51374838176004 |
10 | 13112222113273 |
11 | 41a5953603458 |
12 | 15792a07a48a1 |
13 | 741628659c3a |
14 | 3348c63a1093 |
15 | 17b12b8b859d |
hex | beced575df9 |
13112222113273 has 2 divisors, whose sum is σ = 13112222113274. Its totient is φ = 13112222113272.
The previous prime is 13112222113259. The next prime is 13112222113297. The reversal of 13112222113273 is 37231122221131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12745842497424 + 366379615849 = 3570132^2 + 605293^2 .
It is a cyclic number.
It is not a de Polignac number, because 13112222113273 - 25 = 13112222113241 is a prime.
It is not a weakly prime, because it can be changed into another prime (13112222111273) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556111056636 + 6556111056637.
It is an arithmetic number, because the mean of its divisors is an integer number (6556111056637).
Almost surely, 213112222113273 is an apocalyptic number.
It is an amenable number.
13112222113273 is a deficient number, since it is larger than the sum of its proper divisors (1).
13112222113273 is an equidigital number, since it uses as much as digits as its factorization.
13112222113273 is an evil number, because the sum of its binary digits is even.
The product of its digits is 6048, while the sum is 31.
The spelling of 13112222113273 in words is "thirteen trillion, one hundred twelve billion, two hundred twenty-two million, one hundred thirteen thousand, two hundred seventy-three".
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