Base | Representation |
---|---|
bin | 11000011011000110… |
… | …01111011100110110 |
3 | 1020211211000000022111 |
4 | 30031203033130312 |
5 | 203323213302042 |
6 | 10005040521234 |
7 | 642635143453 |
oct | 141543173466 |
9 | 36754000274 |
10 | 13112244022 |
11 | 561957a009 |
12 | 265b32021a |
13 | 130c711597 |
14 | 8c562682a |
15 | 51b224517 |
hex | 30d8cf736 |
13112244022 has 4 divisors (see below), whose sum is σ = 19668366036. Its totient is φ = 6556122010.
The previous prime is 13112244011. The next prime is 13112244023. The reversal of 13112244022 is 22044221131.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 22044221131 = 23 ⋅958444397.
It is a junction number, because it is equal to n+sod(n) for n = 13112243984 and 13112244002.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13112244023) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3278061004 + ... + 3278061007.
It is an arithmetic number, because the mean of its divisors is an integer number (4917091509).
Almost surely, 213112244022 is an apocalyptic number.
13112244022 is a deficient number, since it is larger than the sum of its proper divisors (6556122014).
13112244022 is an equidigital number, since it uses as much as digits as its factorization.
13112244022 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6556122013.
The product of its (nonzero) digits is 768, while the sum is 22.
Adding to 13112244022 its reverse (22044221131), we get a palindrome (35156465153).
The spelling of 13112244022 in words is "thirteen billion, one hundred twelve million, two hundred forty-four thousand, twenty-two".
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