13112311010131 has 2 divisors, whose sum is σ = 13112311010132. Its totient is φ = 13112311010130.

The previous prime is 13112311010053. The next prime is 13112311010189. The reversal of 13112311010131 is 13101011321131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13112311010131 - 2²¹ = 13112308912979 is a prime.

It is a super-2 number, since 2×13112311010131² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13112311010099 and 13112311010108.

It is not a weakly prime, because it can be changed into another prime (13112311010191) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556155505065 + 6556155505066.

It is an arithmetic number, because the mean of its divisors is an integer number (6556155505066).

Almost surely, 2^{13112311010131} is an apocalyptic number.

13112311010131 is a deficient number, since it is larger than the sum of its proper divisors (1).

13112311010131 is an equidigital number, since it uses as much as digits as its factorization.

13112311010131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54, while the sum is 19.

Adding to 13112311010131 its reverse (13101011321131), we get a palindrome (26213322331262).

The spelling of 13112311010131 in words is "thirteen trillion, one hundred twelve billion, three hundred eleven million, ten thousand, one hundred thirty-one".