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13112313055 = 56739141233
BaseRepresentation
bin11000011011000111…
…00000010011011111
31020211211010112000021
430031203200103133
5203323223004210
610005042213011
7642635551642
oct141543402337
936754115007
1013112313055
115619616966
12265b354167
13130c736b2a
148c5643a59
1551b239bda
hex30d8e04df

13112313055 has 8 divisors (see below), whose sum is σ = 15969623472. Its totient is φ = 10333285248.

The previous prime is 13112313047. The next prime is 13112313077. The reversal of 13112313055 is 55031321131.

13112313055 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13112313055 - 23 = 13112313047 is a prime.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 19570282 + ... + 19570951.

It is an arithmetic number, because the mean of its divisors is an integer number (1996202934).

Almost surely, 213112313055 is an apocalyptic number.

13112313055 is a deficient number, since it is larger than the sum of its proper divisors (2857310417).

13112313055 is an equidigital number, since it uses as much as digits as its factorization.

13112313055 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 39141305.

The product of its (nonzero) digits is 1350, while the sum is 25.

Adding to 13112313055 its reverse (55031321131), we get a palindrome (68143634186).

The spelling of 13112313055 in words is "thirteen billion, one hundred twelve million, three hundred thirteen thousand, fifty-five".

Divisors: 1 5 67 335 39141233 195706165 2622462611 13112313055