13112330043433 has 2 divisors, whose sum is σ = 13112330043434. Its totient is φ = 13112330043432.

The previous prime is 13112330043391. The next prime is 13112330043517. The reversal of 13112330043433 is 33434003321131.

13112330043433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12304359171049 + 807970872384 = 3507757^2 + 898872^2 .

It is a cyclic number.

It is not a de Polignac number, because 13112330043433 - 2²⁵ = 13112296489001 is a prime.

It is a super-3 number, since 3×13112330043433³ (a number of 40 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13112330043395 and 13112330043404.

It is not a weakly prime, because it can be changed into another prime (13112330043733) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556165021716 + 6556165021717.

It is an arithmetic number, because the mean of its divisors is an integer number (6556165021717).

Almost surely, 2^{13112330043433} is an apocalyptic number.

It is an amenable number.

13112330043433 is a deficient number, since it is larger than the sum of its proper divisors (1).

13112330043433 is an equidigital number, since it uses as much as digits as its factorization.

13112330043433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 23328, while the sum is 31.

Adding to 13112330043433 its reverse (33434003321131), we get a palindrome (46546333364564).

The spelling of 13112330043433 in words is "thirteen trillion, one hundred twelve billion, three hundred thirty million, forty-three thousand, four hundred thirty-three".