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13112330110000 = 245411469125411
BaseRepresentation
bin1011111011001111001111…
…0001110100010000110000
31201102112012211102100122221
42332303303301310100300
53204313023002010000
643515415444410424
72522222522650432
oct276636361642060
951375184370587
1013112330110000
1141a59a9566a50
1215793109a6a14
13741644b40524
143348d6874652
1517b1360ec61a
hexbecf3c74430

13112330110000 has 200 divisors, whose sum is σ = 34641032171328. Its totient is φ = 4766916000000.

The previous prime is 13112330109997. The next prime is 13112330110021. The reversal of 13112330110000 is 1103321131.

It is a tau number, because it is divible by the number of its divisors (200).

It is a super-3 number, since 3×131123301100003 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Harshad number since it is a multiple of its sum of digits (16).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 515997295 + ... + 516022705.

Almost surely, 213112330110000 is an apocalyptic number.

13112330110000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13112330110000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (17320516085664).

13112330110000 is an abundant number, since it is smaller than the sum of its proper divisors (21528702061328).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13112330110000 is a wasteful number, since it uses less digits than its factorization.

13112330110000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 30141 (or 30120 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 13112330110000 its reverse (1103321131), we get a palindrome (13113433431131).

The spelling of 13112330110000 in words is "thirteen trillion, one hundred twelve billion, three hundred thirty million, one hundred ten thousand".