13112330310022 has 4 divisors (see below), whose sum is σ = 19668495465036. Its totient is φ = 6556165155010.

The previous prime is 13112330309993. The next prime is 13112330310061. The reversal of 13112330310022 is 22001303321131.

It is a semiprime because it is the product of two primes.

It is a super-3 number, since 3×13112330310022³ (a number of 40 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13112330309975 and 13112330310002.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3278082577504 + ... + 3278082577507.

It is an arithmetic number, because the mean of its divisors is an integer number (4917123866259).

Almost surely, 2^{13112330310022} is an apocalyptic number.

13112330310022 is a deficient number, since it is larger than the sum of its proper divisors (6556165155014).

13112330310022 is an equidigital number, since it uses as much as digits as its factorization.

13112330310022 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6556165155013.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 13112330310022 its reverse (22001303321131), we get a palindrome (35113633631153).

The spelling of 13112330310022 in words is "thirteen trillion, one hundred twelve billion, three hundred thirty million, three hundred ten thousand, twenty-two".