Base | Representation |
---|---|
bin | 10011000101001011100… |
… | …110100101111101011010 |
3 | 11122100112010000222221022 |
4 | 103011023212211331122 |
5 | 132440401224332214 |
6 | 2442212231042442 |
7 | 163506405200231 |
oct | 23051346457532 |
9 | 4570463028838 |
10 | 1311233433434 |
11 | 4661000a8a81 |
12 | 192161510422 |
13 | 968584b3a82 |
14 | 4766d461b18 |
15 | 24195224d8e |
hex | 1314b9a5f5a |
1311233433434 has 8 divisors (see below), whose sum is σ = 1969448369268. Its totient is φ = 654750643680.
The previous prime is 1311233433347. The next prime is 1311233433457. The reversal of 1311233433434 is 4343343321131.
It is a happy number.
It can be written as a sum of positive squares in 2 ways, for example, as 1289167222225 + 22066211209 = 1135415^2 + 148547^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-2 number, since 2×13112334334342 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1311233433394 and 1311233433403.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 433034627 + ... + 433037654.
Almost surely, 21311233433434 is an apocalyptic number.
1311233433434 is a deficient number, since it is larger than the sum of its proper divisors (658214935834).
1311233433434 is an equidigital number, since it uses as much as digits as its factorization.
1311233433434 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 866073040.
The product of its digits is 93312, while the sum is 35.
Adding to 1311233433434 its reverse (4343343321131), we get a palindrome (5654576754565).
The spelling of 1311233433434 in words is "one trillion, three hundred eleven billion, two hundred thirty-three million, four hundred thirty-three thousand, four hundred thirty-four".
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