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13112335417 is a prime number
BaseRepresentation
bin11000011011000111…
…00101110000111001
31020211211011122200111
430031203211300321
5203323224213132
610005042504321
7642636004066
oct141543456071
936754148614
1013112335417
115619631745
12265b3650a1
13130c74406c
148c564bc6d
1551b241647
hex30d8e5c39

13112335417 has 2 divisors, whose sum is σ = 13112335418. Its totient is φ = 13112335416.

The previous prime is 13112335387. The next prime is 13112335421. The reversal of 13112335417 is 71453321131.

13112335417 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13112311081 + 24336 = 114509^2 + 156^2 .

It is an emirp because it is prime and its reverse (71453321131) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13112335417 is a prime.

It is not a weakly prime, because it can be changed into another prime (13112335447) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556167708 + 6556167709.

It is an arithmetic number, because the mean of its divisors is an integer number (6556167709).

Almost surely, 213112335417 is an apocalyptic number.

It is an amenable number.

13112335417 is a deficient number, since it is larger than the sum of its proper divisors (1).

13112335417 is an equidigital number, since it uses as much as digits as its factorization.

13112335417 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 7560, while the sum is 31.

Adding to 13112335417 its reverse (71453321131), we get a palindrome (84565656548).

The spelling of 13112335417 in words is "thirteen billion, one hundred twelve million, three hundred thirty-five thousand, four hundred seventeen".