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131123857 is a prime number
BaseRepresentation
bin1111101000011…
…00101010010001
3100010201210010011
413310030222101
5232031430412
621002234521
73151351204
oct764145221
9303653104
10131123857
116801a327
1237ab5a41
13212201a7
14135b393b
15b7a17a7
hex7d0ca91

131123857 has 2 divisors, whose sum is σ = 131123858. Its totient is φ = 131123856.

The previous prime is 131123803. The next prime is 131123879. The reversal of 131123857 is 758321131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 76895361 + 54228496 = 8769^2 + 7364^2 .

It is an emirp because it is prime and its reverse (758321131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131123857 - 219 = 130599569 is a prime.

It is not a weakly prime, because it can be changed into another prime (131223857) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65561928 + 65561929.

It is an arithmetic number, because the mean of its divisors is an integer number (65561929).

Almost surely, 2131123857 is an apocalyptic number.

It is an amenable number.

131123857 is a deficient number, since it is larger than the sum of its proper divisors (1).

131123857 is an equidigital number, since it uses as much as digits as its factorization.

131123857 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 5040, while the sum is 31.

The square root of 131123857 is about 11450.9325821088. The cubic root of 131123857 is about 508.0353182401.

Adding to 131123857 its reverse (758321131), we get a palindrome (889444988).

The spelling of 131123857 in words is "one hundred thirty-one million, one hundred twenty-three thousand, eight hundred fifty-seven".