Base | Representation |
---|---|
bin | 10011000101001100000… |
… | …000001100010011100111 |
3 | 11122100112120122221020121 |
4 | 103011030000030103213 |
5 | 132440404434102403 |
6 | 2442213030542411 |
7 | 163506516216661 |
oct | 23051400142347 |
9 | 4570476587217 |
10 | 1311240144103 |
11 | 46610397188a |
12 | 192163807a07 |
13 | 968599c3396 |
14 | 476702cb531 |
15 | 24195aed3bd |
hex | 1314c00c4e7 |
1311240144103 has 8 divisors (see below), whose sum is σ = 1326039422400. Its totient is φ = 1296442338048.
The previous prime is 1311240144101. The next prime is 1311240144139. The reversal of 1311240144103 is 3014410421131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1311240144103 - 21 = 1311240144101 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1311240144101) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1475058 + ... + 2190496.
It is an arithmetic number, because the mean of its divisors is an integer number (165754927800).
Almost surely, 21311240144103 is an apocalyptic number.
1311240144103 is a deficient number, since it is larger than the sum of its proper divisors (14799278297).
1311240144103 is an equidigital number, since it uses as much as digits as its factorization.
1311240144103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 736121.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 1311240144103 its reverse (3014410421131), we get a palindrome (4325650565234).
The spelling of 1311240144103 in words is "one trillion, three hundred eleven billion, two hundred forty million, one hundred forty-four thousand, one hundred three".
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