1311241356007 has 8 divisors (see below), whose sum is σ = 1514588946192. Its totient is φ = 1121917737600.

The previous prime is 1311241355987. The next prime is 1311241356013. The reversal of 1311241356007 is 7006531421131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1311241356007 - 2¹⁵ = 1311241323239 is a prime.

It is a super-2 number, since 2×1311241356007² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1311241356037) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3505992744 + ... + 3505993117.

It is an arithmetic number, because the mean of its divisors is an integer number (189323618274).

Almost surely, 2^{1311241356007} is an apocalyptic number.

1311241356007 is a gapful number since it is divisible by the number (17) formed by its first and last digit.

1311241356007 is a deficient number, since it is larger than the sum of its proper divisors (203347590185).

1311241356007 is a wasteful number, since it uses less digits than its factorization.

1311241356007 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7011985889.

The product of its (nonzero) digits is 15120, while the sum is 34.

Adding to 1311241356007 its reverse (7006531421131), we get a palindrome (8317772777138).

The spelling of 1311241356007 in words is "one trillion, three hundred eleven billion, two hundred forty-one million, three hundred fifty-six thousand, seven".