Base | Representation |
---|---|
bin | 10011000101001100000… |
… | …100110100001100001001 |
3 | 11122100112122221111201012 |
4 | 103011030010310030021 |
5 | 132440410241343131 |
6 | 2442213112533305 |
7 | 163506532425221 |
oct | 23051404641411 |
9 | 4570478844635 |
10 | 1311241356041 |
11 | 46610461a391 |
12 | 1921640b1235 |
13 | 9685a028bc6 |
14 | 47670525081 |
15 | 24195c8c52b |
hex | 1314c134309 |
1311241356041 has 8 divisors (see below), whose sum is σ = 1405100589984. Its totient is φ = 1219240720960.
The previous prime is 1311241356037. The next prime is 1311241356059. The reversal of 1311241356041 is 1406531421131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1311241356041 - 22 = 1311241356037 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1311241355989 and 1311241356007.
It is not an unprimeable number, because it can be changed into a prime (1311241316041) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 464648255 + ... + 464651076.
It is an arithmetic number, because the mean of its divisors is an integer number (175637573748).
Almost surely, 21311241356041 is an apocalyptic number.
It is an amenable number.
1311241356041 is a deficient number, since it is larger than the sum of its proper divisors (93859233943).
1311241356041 is an equidigital number, since it uses as much as digits as its factorization.
1311241356041 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 929299431.
The product of its (nonzero) digits is 8640, while the sum is 32.
Adding to 1311241356041 its reverse (1406531421131), we get a palindrome (2717772777172).
The spelling of 1311241356041 in words is "one trillion, three hundred eleven billion, two hundred forty-one million, three hundred fifty-six thousand, forty-one".
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