Base | Representation |
---|---|
bin | 10011000101001100000… |
… | …111000110010000111001 |
3 | 11122100112201001220110012 |
4 | 103011030013012100321 |
5 | 132440410420014421 |
6 | 2442213133431305 |
7 | 163506540466463 |
oct | 23051407062071 |
9 | 4570481056405 |
10 | 1311241954361 |
11 | 466104998969 |
12 | 19216433b535 |
13 | 9685a1a8341 |
14 | 4767063d133 |
15 | 24195d5995b |
hex | 1314c1c6439 |
1311241954361 has 2 divisors, whose sum is σ = 1311241954362. Its totient is φ = 1311241954360.
The previous prime is 1311241954327. The next prime is 1311241954381. The reversal of 1311241954361 is 1634591421131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1147803678736 + 163438275625 = 1071356^2 + 404275^2 .
It is a cyclic number.
It is not a de Polignac number, because 1311241954361 - 222 = 1311237760057 is a prime.
It is not a weakly prime, because it can be changed into another prime (1311241954301) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655620977180 + 655620977181.
It is an arithmetic number, because the mean of its divisors is an integer number (655620977181).
Almost surely, 21311241954361 is an apocalyptic number.
It is an amenable number.
1311241954361 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311241954361 is an equidigital number, since it uses as much as digits as its factorization.
1311241954361 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 77760, while the sum is 41.
The spelling of 1311241954361 in words is "one trillion, three hundred eleven billion, two hundred forty-one million, nine hundred fifty-four thousand, three hundred sixty-one".
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