Base | Representation |
---|---|
bin | 10011000101001100001… |
… | …000100010101101001011 |
3 | 11122100112201210010211222 |
4 | 103011030020202231023 |
5 | 132440411014124003 |
6 | 2442213145512255 |
7 | 163506543634421 |
oct | 23051410425513 |
9 | 4570481703758 |
10 | 1311242333003 |
11 | 466105127399 |
12 | 1921644a268b |
13 | 9685a2ab7a5 |
14 | 476706db111 |
15 | 24195dd1c38 |
hex | 1314c222b4b |
1311242333003 has 2 divisors, whose sum is σ = 1311242333004. Its totient is φ = 1311242333002.
The previous prime is 1311242332987. The next prime is 1311242333017. The reversal of 1311242333003 is 3003332421131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1311242333003 - 24 = 1311242332987 is a prime.
It is a super-3 number, since 3×13112423330033 (a number of 37 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (1311242333053) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655621166501 + 655621166502.
It is an arithmetic number, because the mean of its divisors is an integer number (655621166502).
Almost surely, 21311242333003 is an apocalyptic number.
1311242333003 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311242333003 is an equidigital number, since it uses as much as digits as its factorization.
1311242333003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3888, while the sum is 26.
Adding to 1311242333003 its reverse (3003332421131), we get a palindrome (4314574754134).
The spelling of 1311242333003 in words is "one trillion, three hundred eleven billion, two hundred forty-two million, three hundred thirty-three thousand, three".
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