Base | Representation |
---|---|
bin | 11000011011001000… |
… | …01110010100011011 |
3 | 1020211211111002112212 |
4 | 30031210032110123 |
5 | 203323300022111 |
6 | 10005050225335 |
7 | 642640265303 |
oct | 141544162433 |
9 | 36754432485 |
10 | 13112501531 |
11 | 5619735528 |
12 | 265b42524b |
13 | 130c7a185c |
14 | 8c5692603 |
15 | 51b27598b |
hex | 30d90e51b |
13112501531 has 2 divisors, whose sum is σ = 13112501532. Its totient is φ = 13112501530.
The previous prime is 13112501513. The next prime is 13112501539. The reversal of 13112501531 is 13510521131.
Together with previous prime (13112501513) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13112501531 - 226 = 13045392667 is a prime.
It is a super-2 number, since 2×131125015312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13112501497 and 13112501506.
It is not a weakly prime, because it can be changed into another prime (13112501539) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556250765 + 6556250766.
It is an arithmetic number, because the mean of its divisors is an integer number (6556250766).
Almost surely, 213112501531 is an apocalyptic number.
13112501531 is a deficient number, since it is larger than the sum of its proper divisors (1).
13112501531 is an equidigital number, since it uses as much as digits as its factorization.
13112501531 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 450, while the sum is 23.
The spelling of 13112501531 in words is "thirteen billion, one hundred twelve million, five hundred one thousand, five hundred thirty-one".
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