13112511504133 has 4 divisors (see below), whose sum is σ = 13115457478368. Its totient is φ = 13109565529900.

The previous prime is 13112511504049. The next prime is 13112511504179. The reversal of 13112511504133 is 33140511521131.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13112511504133 - 2⁴¹ = 10913488248581 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13112511504095 and 13112511504104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13112511504733) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1472980441 + ... + 1472989342.

It is an arithmetic number, because the mean of its divisors is an integer number (3278864369592).

Almost surely, 2^{13112511504133} is an apocalyptic number.

It is an amenable number.

13112511504133 is a deficient number, since it is larger than the sum of its proper divisors (2945974235).

13112511504133 is an equidigital number, since it uses as much as digits as its factorization.

13112511504133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2945974234.

The product of its (nonzero) digits is 5400, while the sum is 31.

The spelling of 13112511504133 in words is "thirteen trillion, one hundred twelve billion, five hundred eleven million, five hundred four thousand, one hundred thirty-three".