13112523403 has 4 divisors (see below), whose sum is σ = 14985741040. Its totient is φ = 11239305768.

The previous prime is 13112523401. The next prime is 13112523407. The reversal of 13112523403 is 30432521131.

It is a happy number.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30432521131 = 23203 ⋅1311577.

It is a cyclic number.

It is not a de Polignac number, because 13112523403 - 2¹ = 13112523401 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13112523401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 936608808 + ... + 936608821.

It is an arithmetic number, because the mean of its divisors is an integer number (3746435260).

Almost surely, 2^13112523403 is an apocalyptic number.

13112523403 is a deficient number, since it is larger than the sum of its proper divisors (1873217637).

13112523403 is an equidigital number, since it uses as much as digits as its factorization.

13112523403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1873217636.

The product of its (nonzero) digits is 2160, while the sum is 25.

The spelling of 13112523403 in words is "thirteen billion, one hundred twelve million, five hundred twenty-three thousand, four hundred three".