Base | Representation |
---|---|
bin | 10011000101001100111… |
… | …000111000010001001000 |
3 | 11122100120121121220111202 |
4 | 103011030320320101020 |
5 | 132440422240113412 |
6 | 2442214321243332 |
7 | 163510056430655 |
oct | 23051470702110 |
9 | 4570517556452 |
10 | 1311255004232 |
11 | 4661112a1488 |
12 | 192168793548 |
13 | 9685cac7164 |
14 | 47672278c2c |
15 | 241970863c2 |
hex | 1314ce38448 |
1311255004232 has 32 divisors (see below), whose sum is σ = 2515864428000. Its totient is φ = 640358847744.
The previous prime is 1311255004181. The next prime is 1311255004237. The reversal of 1311255004232 is 2324005521131.
It is a super-2 number, since 2×13112550042322 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1311255004195 and 1311255004204.
It is not an unprimeable number, because it can be changed into a prime (1311255004237) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 16178144 + ... + 16258992.
It is an arithmetic number, because the mean of its divisors is an integer number (78620763375).
Almost surely, 21311255004232 is an apocalyptic number.
It is an amenable number.
1311255004232 is a deficient number, since it is larger than the sum of its proper divisors (1204609423768).
1311255004232 is a wasteful number, since it uses less digits than its factorization.
1311255004232 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 128045 (or 128041 counting only the distinct ones).
The product of its (nonzero) digits is 7200, while the sum is 29.
The spelling of 1311255004232 in words is "one trillion, three hundred eleven billion, two hundred fifty-five million, four thousand, two hundred thirty-two".
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