1311300000023 has 32 divisors (see below), whose sum is σ = 1515402302400. Its totient is φ = 1123904710656.

The previous prime is 1311300000007. The next prime is 1311300000029. The reversal of 1311300000023 is 3200000031131.

It is not a de Polignac number, because 1311300000023 - 2⁴ = 1311300000007 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1311299999953 and 1311300000007.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1311300000029) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 12954773 + ... + 13055601.

It is an arithmetic number, because the mean of its divisors is an integer number (47356321950).

Almost surely, 2^{1311300000023} is an apocalyptic number.

1311300000023 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

1311300000023 is a deficient number, since it is larger than the sum of its proper divisors (204102302377).

1311300000023 is a wasteful number, since it uses less digits than its factorization.

1311300000023 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 101651.

The product of its (nonzero) digits is 54, while the sum is 14.

Adding to 1311300000023 its reverse (3200000031131), we get a palindrome (4511300031154).

The spelling of 1311300000023 in words is "one trillion, three hundred eleven billion, three hundred million, twenty-three", and thus it is an aban number.