13113003443 has 2 divisors, whose sum is σ = 13113003444. Its totient is φ = 13113003442.

The previous prime is 13113003401. The next prime is 13113003451. The reversal of 13113003443 is 34430031131.

13113003443 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (34430031131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13113003443 - 2²² = 13108809139 is a prime.

It is a super-2 number, since 2×13113003443² (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13113003143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556501721 + 6556501722.

It is an arithmetic number, because the mean of its divisors is an integer number (6556501722).

Almost surely, 2^13113003443 is an apocalyptic number.

13113003443 is a deficient number, since it is larger than the sum of its proper divisors (1).

13113003443 is an equidigital number, since it uses as much as digits as its factorization.

13113003443 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 13113003443 its reverse (34430031131), we get a palindrome (47543034574).

The spelling of 13113003443 in words is "thirteen billion, one hundred thirteen million, three thousand, four hundred forty-three".