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13113012109913 is a prime number
BaseRepresentation
bin1011111011010001110001…
…1011011100001001011001
31201102120222100201112122222
42332310130123130021121
53204320422100004123
643520011250153425
72522245443602402
oct276643433341131
951376870645588
1013113012109913
1141a6219531641
121579481282875
13741723219881
1433495d2849a9
1517b175e166c8
hexbed1c6dc259

13113012109913 has 2 divisors, whose sum is σ = 13113012109914. Its totient is φ = 13113012109912.

The previous prime is 13113012109909. The next prime is 13113012110047. The reversal of 13113012109913 is 31990121031131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12104359473424 + 1008652636489 = 3479132^2 + 1004317^2 .

It is a cyclic number.

It is not a de Polignac number, because 13113012109913 - 22 = 13113012109909 is a prime.

It is a super-3 number, since 3×131130121099133 (a number of 40 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (13113012109903) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556506054956 + 6556506054957.

It is an arithmetic number, because the mean of its divisors is an integer number (6556506054957).

Almost surely, 213113012109913 is an apocalyptic number.

It is an amenable number.

13113012109913 is a deficient number, since it is larger than the sum of its proper divisors (1).

13113012109913 is an equidigital number, since it uses as much as digits as its factorization.

13113012109913 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4374, while the sum is 35.

The spelling of 13113012109913 in words is "thirteen trillion, one hundred thirteen billion, twelve million, one hundred nine thousand, nine hundred thirteen".