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1311302234111 = 5324741551587
BaseRepresentation
bin10011000101001111101…
…101000010111111111111
311122100200220111102201112
4103011033231002333333
5132441021332442421
62442223125432235
7163511202040262
oct23051755027777
94570626442645
101311302234111
11466135a1aa41
1219218056b67b
139686982272c
1447678650cd9
152419b2b545b
hex1314fb42fff

1311302234111 has 4 divisors (see below), whose sum is σ = 1336043785752. Its totient is φ = 1286560682472.

The previous prime is 1311302234069. The next prime is 1311302234131. The reversal of 1311302234111 is 1114322031131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1311302234111 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1311302234131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12370775741 + ... + 12370775846.

It is an arithmetic number, because the mean of its divisors is an integer number (334010946438).

Almost surely, 21311302234111 is an apocalyptic number.

1311302234111 is a deficient number, since it is larger than the sum of its proper divisors (24741551641).

1311302234111 is an equidigital number, since it uses as much as digits as its factorization.

1311302234111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 24741551640.

The product of its (nonzero) digits is 432, while the sum is 23.

Adding to 1311302234111 its reverse (1114322031131), we get a palindrome (2425624265242).

The spelling of 1311302234111 in words is "one trillion, three hundred eleven billion, three hundred two million, two hundred thirty-four thousand, one hundred eleven".

Divisors: 1 53 24741551587 1311302234111