13113030299947 has 2 divisors, whose sum is σ = 13113030299948. Its totient is φ = 13113030299946.

The previous prime is 13113030299861. The next prime is 13113030299969. The reversal of 13113030299947 is 74999203031131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13113030299947 - 2³¹ = 13110882816299 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13113030299894 and 13113030299903.

It is not a weakly prime, because it can be changed into another prime (13113030293947) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556515149973 + 6556515149974.

It is an arithmetic number, because the mean of its divisors is an integer number (6556515149974).

Almost surely, 2^{13113030299947} is an apocalyptic number.

13113030299947 is a deficient number, since it is larger than the sum of its proper divisors (1).

13113030299947 is an equidigital number, since it uses as much as digits as its factorization.

13113030299947 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1102248, while the sum is 52.

The spelling of 13113030299947 in words is "thirteen trillion, one hundred thirteen billion, thirty million, two hundred ninety-nine thousand, nine hundred forty-seven".