1311304434440 has 384 divisors, whose sum is σ = 4141214380800. Its totient is φ = 360869160960.

The previous prime is 1311304434437. The next prime is 1311304434493. The reversal of 1311304434440 is 444344031131.

It is a super-2 number, since 2×1311304434440² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1311304434397 and 1311304434406.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 21150206 + ... + 21212114.

It is an arithmetic number, because the mean of its divisors is an integer number (10784412450).

Almost surely, 2^{1311304434440} is an apocalyptic number.

1311304434440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1311304434440, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2070607190400).

1311304434440 is an abundant number, since it is smaller than the sum of its proper divisors (2829909946360).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1311304434440 is a wasteful number, since it uses less digits than its factorization.

1311304434440 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 61997 (or 61970 counting only the distinct ones).

The product of its (nonzero) digits is 27648, while the sum is 32.

Adding to 1311304434440 its reverse (444344031131), we get a palindrome (1755648465571).

The spelling of 1311304434440 in words is "one trillion, three hundred eleven billion, three hundred four million, four hundred thirty-four thousand, four hundred forty".