1311305352341 has 4 divisors (see below), whose sum is σ = 1311335424300. Its totient is φ = 1311275280384.

The previous prime is 1311305352319. The next prime is 1311305352353. The reversal of 1311305352341 is 1432535031131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 828926486116 + 482378866225 = 910454^2 + 694535^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1311305352341 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1311305352298 and 1311305352307.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1311305354341) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14970476 + ... + 15057813.

It is an arithmetic number, because the mean of its divisors is an integer number (327833856075).

Almost surely, 2^{1311305352341} is an apocalyptic number.

It is an amenable number.

1311305352341 is a deficient number, since it is larger than the sum of its proper divisors (30071959).

1311305352341 is an equidigital number, since it uses as much as digits as its factorization.

1311305352341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 30071958.

The product of its (nonzero) digits is 16200, while the sum is 32.

The spelling of 1311305352341 in words is "one trillion, three hundred eleven billion, three hundred five million, three hundred fifty-two thousand, three hundred forty-one".