1311310321931 has 2 divisors, whose sum is σ = 1311310321932. Its totient is φ = 1311310321930.

The previous prime is 1311310321901. The next prime is 1311310321949. The reversal of 1311310321931 is 1391230131131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1311310321931 - 2²² = 1311306127627 is a prime.

It is a super-2 number, since 2×1311310321931² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1311310321894 and 1311310321903.

It is not a weakly prime, because it can be changed into another prime (1311310321901) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655655160965 + 655655160966.

It is an arithmetic number, because the mean of its divisors is an integer number (655655160966).

Almost surely, 2^{1311310321931} is an apocalyptic number.

1311310321931 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311310321931 is an equidigital number, since it uses as much as digits as its factorization.

1311310321931 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1458, while the sum is 29.

The spelling of 1311310321931 in words is "one trillion, three hundred eleven billion, three hundred ten million, three hundred twenty-one thousand, nine hundred thirty-one".