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131131044223 = 239563974539
BaseRepresentation
bin111101000100000000…
…1001111000101111111
3110112110202012020121121
41322020001033011333
54122024021403343
6140124001211411
712321356325244
oct1721001170577
9415422166547
10131131044223
1150681068423
12214b7630b67
13c49a30487a
1464bd7a95cb
1536272ccaed
hex1e8804f17f

131131044223 has 8 divisors (see below), whose sum is σ = 131913734400. Its totient is φ = 130350304728.

The previous prime is 131131044221. The next prime is 131131044241. The reversal of 131131044223 is 322440131131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 131131044223 - 21 = 131131044221 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131131044221) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 352713 + ... + 621826.

It is an arithmetic number, because the mean of its divisors is an integer number (16489216800).

Almost surely, 2131131044223 is an apocalyptic number.

131131044223 is a deficient number, since it is larger than the sum of its proper divisors (782690177).

131131044223 is an equidigital number, since it uses as much as digits as its factorization.

131131044223 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 975341.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 131131044223 its reverse (322440131131), we get a palindrome (453571175354).

The spelling of 131131044223 in words is "one hundred thirty-one billion, one hundred thirty-one million, forty-four thousand, two hundred twenty-three".

Divisors: 1 239 563 134557 974539 232914821 548665457 131131044223