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131131244224344 = 233713172311668029
BaseRepresentation
bin11101110100001101011111…
…001110110001111101011000
3122012022000122212121002210210
4131310031133032301331120
5114141423242010134334
61142520510103411120
736422630322024210
oct3564153716617530
9565260585532723
10131131244224344
11388674a2864431
121285a144453aa0
135822814432270
142454b01033240
151026057ee75e9
hex77435f3b1f58

131131244224344 has 384 divisors, whose sum is σ = 429989854694400. Its totient is φ = 32444997672960.

The previous prime is 131131244224333. The next prime is 131131244224349. The reversal of 131131244224344 is 443422442131131.

It is a Harshad number since it is a multiple of its sum of digits (39).

It is a nude number because it is divisible by every one of its digits.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131131244224349) by changing a digit.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 195961722 + ... + 196629750.

It is an arithmetic number, because the mean of its divisors is an integer number (1119765246600).

Almost surely, 2131131244224344 is an apocalyptic number.

131131244224344 is a gapful number since it is divisible by the number (14) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131131244224344, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (214994927347200).

131131244224344 is an abundant number, since it is smaller than the sum of its proper divisors (298858610470056).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131131244224344 is a wasteful number, since it uses less digits than its factorization.

131131244224344 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 668403 (or 668382 counting only the distinct ones).

The product of its digits is 221184, while the sum is 39.

Adding to 131131244224344 its reverse (443422442131131), we get a palindrome (574553686355475).

The spelling of 131131244224344 in words is "one hundred thirty-one trillion, one hundred thirty-one billion, two hundred forty-four million, two hundred twenty-four thousand, three hundred forty-four".