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1311320002022 = 2655660001011
BaseRepresentation
bin10011000101010000110…
…000110100110111100110
311122100202010221010201022
4103011100300310313212
5132441040410031042
62442225002331142
7163511506051622
oct23052060646746
94570663833638
101311320002022
11466144a56268
121921864b9ab2
1396870403ba4
144767ab58182
152419cb24cd2
hex13150c34de6

1311320002022 has 4 divisors (see below), whose sum is σ = 1966980003036. Its totient is φ = 655660001010.

The previous prime is 1311320002021. The next prime is 1311320002049. The reversal of 1311320002022 is 2202000231131.

It is a semiprime because it is the product of two primes.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1311320002021) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 327830000504 + ... + 327830000507.

It is an arithmetic number, because the mean of its divisors is an integer number (491745000759).

Almost surely, 21311320002022 is an apocalyptic number.

1311320002022 is a deficient number, since it is larger than the sum of its proper divisors (655660001014).

1311320002022 is an equidigital number, since it uses as much as digits as its factorization.

1311320002022 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 655660001013.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 1311320002022 its reverse (2202000231131), we get a palindrome (3513320233153).

The spelling of 1311320002022 in words is "one trillion, three hundred eleven billion, three hundred twenty million, two thousand, twenty-two".

Divisors: 1 2 655660001011 1311320002022