131132002013 has 4 divisors (see below), whose sum is σ = 131132738940. Its totient is φ = 131131265088.

The previous prime is 131132001983. The next prime is 131132002063. The reversal of 131132002013 is 310200231131.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 310200231131 = 7 ⋅44314318733.

It can be written as a sum of positive squares in 2 ways, for example, as 26128136164 + 105003865849 = 161642^2 + 324043^2 .

It is a cyclic number.

It is not a de Polignac number, because 131132002013 - 2²² = 131127807709 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131132001982 and 131132002000.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131132002063) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 82133 + ... + 518661.

It is an arithmetic number, because the mean of its divisors is an integer number (32783184735).

Almost surely, 2^131132002013 is an apocalyptic number.

It is an amenable number.

131132002013 is a deficient number, since it is larger than the sum of its proper divisors (736927).

131132002013 is an equidigital number, since it uses as much as digits as its factorization.

131132002013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 736926.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 131132002013 its reverse (310200231131), we get a palindrome (441332233144).

The spelling of 131132002013 in words is "one hundred thirty-one billion, one hundred thirty-two million, two thousand, thirteen".